Free C++ Institute CLA-11-03 Practice Exam with Questions & Answers | Set: 2

The expression 10 - 2 / 5 * 10 / 2 - 1 is evaluated based on the standard precedence rules in C. Division and multiplication have higher precedence than addition and subtrac-tion, and they are evaluated from left to right:

1.2 / 5 evaluates to 0 (integer division).

2.0 * 10 evaluates to 0.

3.0 / 2 evaluates to 0.

4.10 - 0 - 1 evaluates to 9.

Therefore, the correct answer is "The program outputs 9."

The provided program has a few key points to consider:

1.fun is a function that uses a static variable i. This means i retains its value between function calls. It's initialized to 1 and then incremented by 2 each time fun is called.

2.The main function calls fun twice, assigning the results to k and l (though there's a typo in the variable name l, it should be l = fun();, not 1 = fun();).

Let's step through the code:

•First call to fun: i starts at 1, increments by 2, so i becomes 3. This value (3) is as-signed to k.

•Second call to fun: i is now 3, increments by 2 again, so i becomes 5. This value (5) is assigned to l.

Finally, the printf statement attempts to print l - k, which is 5 - 3, resulting in 2.

So, the correct answer is:

A. The program outputs 2.