Free AHA CHFM Practice Exam with Questions & Answers | Set: 3

NFPA 25 (2011), Standard for the Inspection, Testing, and Maintenance of Water-Based Fire Protection Systems, specifies that a fire pump flow test must be performed annually. This ensures that the pump delivers adequate flow and pressure under actual operating conditions. Weekly no-flow (churn) tests are also required, but full-flow condition testing is mandated at least once per year.

For electrical systems, real power (kW) is obtained by multiplying apparent power (kVA) by the power factor (PF):

kW = kVA × PF

This formula gives the average power consumed by a single-phase motor.

C. KVA × PF (Correct): Standard power equation for real power.

A. KVA / PF: Incorrect; dividing by PF would increase kVA, not convert to kW.

B. kW × PF / 1,000: Incorrect; kW already accounts for PF, and the division by 1,000 is irrelevant here.

D. amps / PF: Incomplete and not dimensionally correct.

According to standard accounting practices, when an overhaul or replacement extends the useful life of an asset, it is considered a capital expenditure. Operating costs are day-to-day expenses; contingency is reserved budget for unforeseen costs; non-depreciable refers to land, not equipment.

To stay within the $5,000,000 annual budget, the facilities department must reduce monthly spending to $337,500 for the remaining 8 months.

Written fire procedures must include the method for promptly notifying the fire department or emergency response agency, ensuring immediate response to protect life and property. Evacuation routes and equipment locations are important operational elements, but the mandatory code requirement is a defined notification procedure.

NFPA 70 (NEC) Article 110.26(A)(1) establishes the depth of working space in front of electrical equipment. For systems 0–150 volts to ground, the minimum depth is 3 ft (36 in.); for 151–600 volts, the required depth is 3–4 ft depending on the condition (exposed live parts and grounded surfaces). In healthcare facilities, unless a more stringent “condition” applies, the baseline minimum clearance encountered for 600 V or less is 36 inches.

Calculation:

Vendor 1 = $25,000 annually

Vendor 2 = $970 × 30 = $29,100 annually

Vendor 3 = $950 × 26 = $24,700 annually

Vendor 4 = $2,100 × 12 = $25,200 annually

Least expensive = Vendor 3 ($24,700).

A Hazard Vulnerability Analysis (HVA) evaluates probability/likelihood of events, impact/consequences on operations and safety, and surge/demand effects on services to prioritize preparedness and mitigation. While cost considerations inform later planning, the core HVA scoring focuses on likelihood, consequences, and demand effects.

Overage = 140 cu. ft.

Each small cylinder = 25 cu. ft.

140 ÷ 25 = 5.6 → minimum 6 needed if rounding up. However, since the question asks for the minimum number to remove to get below the limit, removing 5 cylinders = 125 cu. ft. would still leave 15 cu. ft. over the limit. Therefore, 6 cylinders must be removed.

Correct answer = C (6), not B.

The transformer voltage ratio is determined by the turns ratio:

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=

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V

p

​

V

s

​

​

=

N

p

​

N

s

​

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=

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×

127

254

=

220

×

0.5

=

110

volts

V

s

​

=V

p

​

×

254

127

​

=220×0.5=110volts

A. 110 (Correct): Secondary voltage is half of the primary because turns ratio = 0.5.

B. 127: Incorrect, not consistent with ratio.

C. 220: Would occur only if turns ratio = 1.

D. 440: Would occur if secondary had twice as many turns as primary.